Star Trek Anyone know math?

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POSTS: 22

Report this Jan. 20 2005, 11:22 pm

Hey guys, I hope I'm allowd to post this on a Trek board. I usually read here and don't post so you probably don't recognize the name. Anyway, does anyone know about trig identities or logarithms? I have a final tomorrow and can't figure out 3 practice problems. If anyone thinks they could help post back or contact me on MSN at daenigma87@msn.com

AquamonkeyEG

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Report this Jan. 21 2005, 1:24 am

oh man it's been a while since i had to do math without a calculator.

AlphaJohn

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Report this Jan. 21 2005, 6:14 am

Post the problems...we'll be glad to help. You shouldn't post an e-mail address (bad idea).

8472Zo

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POSTS: 1973

Report this Jan. 22 2005, 6:34 am

This is as far as we got in Ten Forward.
This was posted to us a couple of nights ago.

[(sec - 1) / (sec + 1)] + [(cos - 1) / (cos + 1)]

(sec/sin) - (sin/cos)

(sec x sec) / (csc x csc)

(sec/sin) - (sin/cos)

.848125 = 1.001125 (to the power of) 25 t

Soh Cah Toa
Sin Cos Tan

Cho Sha Cao
(these I can't remember, they are cosecant, cotangent and secant)
Therefore
Cho Sha Cao
Cosecant Secant Cotangent (I think?!

Sin = 1/sec
Cos = 1/csc
Tan = 1/Cot

What is t?

actually csc = 1/sin and sec = 1/cos

For the log question

If x = b (to the power of y)
y = log x
b

Therefore

t = log .848125
1.001125

MiralTheLovelyLass

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Report this Jan. 22 2005, 6:35 am

Holy crap!

8472Zo

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POSTS: 1973

Report this Jan. 22 2005, 6:37 am

Yeah, I know.

ssmukhi

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Report this Jan. 22 2005, 12:20 pm

You showed us the solution but what was the question?

8472Zo

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POSTS: 1973

Report this Jan. 22 2005, 1:25 pm

Here is the link to the original thread:

Does anybody know Math(s)

ssmukhi

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POSTS: 65791

Report this Jan. 24 2005, 6:39 am

convert the left side to cosine:

[(1 / cos - 1)/ (1 / cos + 1)]

using cos as the common denominator:

[ (1 - cos ) / cos] / [ (1 + cos) / cos]

the cos in the denominator cancels out so we have
(1 - cos) / ( 1 + cos)

adding to the second part we have
(1 - cos) / ( 1 + cos) + (cos -1) / (cos + 1)

we now have a common denominator so it becomes

( 1 - cos + cos - 1 ) / (cos + 1)

the numerator adds to 0 so the final answer: 0

ssmukhi

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POSTS: 65791

Report this Jan. 24 2005, 6:49 am

Quote (LadyZo @ Jan. 22 2005, 11:34 am)

(sec/sin) - (sin/cos)

convert left numerator side to cos

( 1 / cos / sin )

1 / (cos . sin )

common denominator is cos . sin

( 1 - sin ^ 2) / (cos . sin )

cos ^ 2 / (cos . sin)

cos / sin

= cot

ssmukhi

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POSTS: 65791

Report this Jan. 24 2005, 6:52 am

I don't understand the 3rd problem. Does sec x sec read as secant of x secant or secant of x timex sec (of what?)

The 4th is the same as the 2nd.

XWARP

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POSTS: 54

Report this Jan. 26 2005, 2:29 am

DON'T WORRY ABOUT ALL OF THAT MATH. JUST PUSH THE GREEN BUTTON AND THE SHIP WILL GO TO WARP!